Calculate $\alpha$ for $0.1 \ M$ acetic acid $(K_{a} = 1.0 \times 10^{-5})$.

$A$ monoprotic acid in a $0.1 \ M$ solution ionizes to $0.001 \%$. Its ionisation constant is

If the dissociation constant of an acid $HA$ is $1 \times 10^{-5}$,the $pH$ of a $0.1 \ M$ solution of the acid will be approximately

The degree of ionization of $0.4 \ M$ acetic acid will be $(K_{a} = 1.8 \times 10^{-5})$.

The $pH$ of $0.1 \ M$ acetic acid is $3$. The dissociation constant of the acid will be:

Calculate the molar concentration of a weak monobasic acid if the acid dissociation constant $K_a = 1.8 \times 10^{-5}$ and the degree of dissociation $\alpha = 0.01$.