Calculate the change in internal energy (Delt | vedclass

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(B) Given: $\Delta H = -92.2\, kJ$,$P = 40\, atm$,$\Delta V = -1\, L$.Using the relation: $\Delta H = \Delta U + P\Delta V$Therefore: $\Delta U = \Del

Vedclass · Accepted Answer

$-88\, kJ$

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(B) Given: $\Delta H = -92.2\, kJ$,$P = 40\, atm$,$\Delta V = -1\, L$.Using the relation: $\Delta H = \Delta U + P\Delta V$Therefore: $\Delta U = \Delta H - P\Delta V$First,convert $P\Delta V$ from $atm\, L$ to $kJ$ using the conversion factor $1\, atm\, L = 101.325\, J = 0.101325\, kJ$.$P\Delta V = 40\, atm 	imes (-1\, L) = -40\, atm\, L$$P\Delta V = -40 	imes 0.101325\, kJ = -4.053\, kJ$Now,calculate $\Delta U$:$\Delta U = -92.2\, kJ - (-4.053\, kJ)$$\Delta U = -92.2\, kJ + 4.053\, kJ = -88.147\, kJ$Rounding to the nearest integer,we get $\Delta U \approx -88\, kJ$.

Calculate the change in internal energy $(\Delta U)$ if $\Delta H = -92.2\, kJ$,$P = 40\, atm$,and $\Delta V = -1\, L$.

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