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(A) For $Cl$ $(Z=17, A=35)$: Protons $(p) = Z = 17$. Electrons $(e^{-}) = Z = 17$. Neutrons $(n) = A - Z = 35 - 17 = 18$.For $Cl^{-}$: Protons $(p) =

Vedclass · Accepted Answer

$Cl$: $e^{-}=17, p=17, n=18$; $Cl^{-}$: $e^{-}=18, p=17, n=18$; $Cl_{2}$: $e^{-}=34, p=34, n=36$

Vedclass · Answer

(A) For $Cl$ $(Z=17, A=35)$: Protons $(p) = Z = 17$. Electrons $(e^{-}) = Z = 17$. Neutrons $(n) = A - Z = 35 - 17 = 18$.For $Cl^{-}$: Protons $(p) = 17$. Electrons $(e^{-}) = 17 + 1 = 18$. Neutrons $(n) = 18$.For $Cl_{2}$: Protons $(p) = 2 	imes 17 = 34$. Electrons $(e^{-}) = 2 	imes 17 = 34$. Neutrons $(n) = 2 	imes 18 = 36$.Thus, the correct values are: $Cl: (17, 17, 18)$, $Cl^{-}: (18, 17, 18)$, $Cl_{2}: (34, 34, 36)$.

Calculate the number of electrons, protons, and neutrons in $Cl_{2}$, $Cl$, and $Cl^{-}$. (Given for $Cl$: $Z = 17$ and $A = 35$)

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