Calculate the oxidation number of C in glucos | vedclass

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Question

(A) The chemical formula of glucose is $C_{6}H_{12}O_{6}$.Let the oxidation number of $C$ be $x$.Using the oxidation states of $H$ $(+1)$ and $O$ $(-2

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(A) The chemical formula of glucose is $C_{6}H_{12}O_{6}$.Let the oxidation number of $C$ be $x$.Using the oxidation states of $H$ $(+1)$ and $O$ $(-2)$,we set the sum of oxidation numbers to $0$:$6(x) + 12(+1) + 6(-2) = 0$$6x + 12 - 12 = 0$$6x = 0$$x = 0$Therefore,the average oxidation number of $C$ in glucose is $0$.

Calculate the oxidation number of $C$ in glucose $(C_{6}H_{12}O_{6})$.

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