(A) The relationship between molar conductivity $(\Lambda_{m})$ and conductivity $(k)$ is given by the formula: $\Lambda_{m} = \frac{1000 \times k}{c}

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$8.144 \times 10^{-3} \ \Omega^{-1} \ cm^{-1}$

(A) The relationship between molar conductivity $(\Lambda_{m})$ and conductivity $(k)$ is given by the formula: $\Lambda_{m} = \frac{1000 \times k}{c}$.Rearranging the formula to solve for conductivity $(k)$: $k = \frac{\Lambda_{m} \times c}{1000}$.Given values: $\Lambda_{m} = 407.2 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ and $c = 0.02 \ M$.Substituting the values: $k = \frac{407.2 \times 0.02}{1000}$.$k = \frac{8.144}{1000} = 8.144 \times 10^{-3} \ \Omega^{-1} \ cm^{-1}$.

Class 12 Chemistry Electrochemistry Conductor and Conductance and Cell constant

Medium

Calculate the conductivity of $0.02 \ M$ electrolyte solution if its molar conductivity is $407.2 \ \Omega^{-1} \ cm^2 \ mol^{-1}$.

MHT CET 2023 All MHT CET

A
$8.144 \times 10^{-3} \ \Omega^{-1} \ cm^{-1}$
B
$4.072 \times 10^{-3} \ \Omega^{-1} \ cm^{-1}$
C
$7.15 \times 10^{-3} \ \Omega^{-1} \ cm^{-1}$
D
$6.055 \times 10^{-3} \ \Omega^{-1} \ cm^{-1}$

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The equivalent conductance at infinite dilution $\wedge^0$ for electrolytes $BA$ and $CA$ are $140$ and $120 \ S \ cm^2 \ eq^{-1}$,respectively. The equivalent conductance at infinite dilution for $BX$ is $198 \ S \ cm^2 \ eq^{-1}$. The $\wedge^0$ (in $S \ cm^2 \ eq^{-1}$) of $CX$ is:

Medium

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$A$ conductivity cell shows a resistance of $600 \ \Omega$. If the conductivity of $0.01 \ M \ KCl$ is $0.0015 \ \Omega^{-1} \ cm^{-1}$,what is the cell constant (in $cm^{-1}$)?

MediumMHT CET 2021

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The resistance of a conductivity cell containing $0.01 \, M \, KCl$ solution at $298 \, K$ is $1750 \, \Omega$. If the conductivity of $0.01 \, M \, KCl$ solution at $298 \, K$ is $0.152 \times 10^{-3} \, S \, cm^{-1}$,then the cell constant of the conductivity cell is $.......... \, \times 10^{-3} \, cm^{-1}$.

MediumJEE MAIN 2022

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If the values of $\Lambda_{\infty}$ of $NH_4Cl$,$NaOH$ and $NaCl$ are $130$,$217$ and $109 \ ohm^{-1} \ cm^2 \ equiv^{-1}$ respectively,the $\Lambda_{\infty}$ of $NH_4OH$ in $ohm^{-1} \ cm^2 \ equiv^{-1}$ is:

MediumAP EAMCET 2011

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Identify True $(T)$ or False $(F)$ for the following statements :
$(i)$ As temperature of solution is more,then conductivity is more.
$(ii)$ Conductivity of $Cu \propto$ temperature.
$(iii)$ As temperature increases,conductivity of $Cu$ decreases.

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Calculate the conductivity of $0.02 \ M$ electrolyte solution if its molar conductivity is $407.2 \ \Omega^{-1} \ cm^2 \ mol^{-1}$.

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The equivalent conductance at infinite dilution $\wedge^0$ for electrolytes $BA$ and $CA$ are $140$ and $120 \ S \ cm^2 \ eq^{-1}$,respectively. The equivalent conductance at infinite dilution for $BX$ is $198 \ S \ cm^2 \ eq^{-1}$. The $\wedge^0$ (in $S \ cm^2 \ eq^{-1}$) of $CX$ is:

$A$ conductivity cell shows a resistance of $600 \ \Omega$. If the conductivity of $0.01 \ M \ KCl$ is $0.0015 \ \Omega^{-1} \ cm^{-1}$,what is the cell constant (in $cm^{-1}$)?

If the values of $\Lambda_{\infty}$ of $NH_4Cl$,$NaOH$ and $NaCl$ are $130$,$217$ and $109 \ ohm^{-1} \ cm^2 \ equiv^{-1}$ respectively,the $\Lambda_{\infty}$ of $NH_4OH$ in $ohm^{-1} \ cm^2 \ equiv^{-1}$ is:

Identify True $(T)$ or False $(F)$ for the following statements :$(i)$ As temperature of solution is more,then conductivity is more.$(ii)$ Conductivity of $Cu \propto$ temperature.$(iii)$ As temperature increases,conductivity of $Cu$ decreases.

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Identify True $(T)$ or False $(F)$ for the following statements :
$(i)$ As temperature of solution is more,then conductivity is more.
$(ii)$ Conductivity of $Cu \propto$ temperature.
$(iii)$ As temperature increases,conductivity of $Cu$ decreases.