Calculate the degree of dissociation of $0.01 \ M$ acetic acid at $25^{\circ} C$ given that the molar conductivity at concentration $c$ is $\Lambda_{c} = 15.0 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ and the limiting molar conductivity is $\Lambda_0 = 300 \ \Omega^{-1} \ cm^2 \ mol^{-1}$.

  • A
    $0.042$
  • B
    $0.035$
  • C
    $0.025$
  • D
    $0.05$

Explore More

Similar Questions

Which solution of $NaNO_3$ will have maximum specific conductance in $N$?

The electrodes of a conductivity cell are $3 \text{ cm}$ apart and have a cross-sectional area of $4 \text{ cm}^2$. The cell constant of the cell (in $\text{cm}^{-1}$) is

$A$ conductivity cell dipped in $0.05 \ M$ $KCl$ has resistance $600 \ \Omega$. If conductivity is $0.0012 \ \Omega^{-1} \ cm^{-1}$,what is the value of cell constant (in $cm^{-1}$)?

Which of the following expressions correctly represents the equivalent conductance at infinite dilution of $Al_2(SO_4)_3$? Given that $\Lambda_{Al^{3+}}^o$ and $\Lambda_{SO_4^{2-}}^o$ are the equivalent conductances at infinite dilution of the respective ions.

State Kohlrausch's law of independent migration of ions and explain its applications.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo