Calculate the density of an aqueous solution | vedclass

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Question

(C) The relationship between molarity $(M)$,molality $(m)$,and density $(d)$ is given by the formula: $m = \frac{1000 	imes M}{1000 	imes d - M 	im

Vedclass · Accepted Answer

$1.20$

Vedclass · Answer

(C) The relationship between molarity $(M)$,molality $(m)$,and density $(d)$ is given by the formula: $m = \frac{1000 	imes M}{1000 	imes d - M 	imes M_B}$ Rearranging for density $(d)$: $d = \frac{M}{m} + \frac{M 	imes M_B}{1000} = \frac{1.44}{1.5} + \frac{1.44 	imes 166}{1000}$ $d = 0.96 + 0.23904 = 1.19904 \ g \ mL^{-1} \approx 1.20 \ g \ mL^{-1}$ Here,$M = 1.44 \ mol \ L^{-1}$,$m = 1.5 \ mol \ kg^{-1}$,and $M_B (KI) = 166 \ g \ mol^{-1}$.

Calculate the density of an aqueous solution of $KI$,if its molarity and molality are $1.44 \ M$ and $1.5 \ mol \ kg^{-1}$ respectively. (in $g \ mL^{-1}$)

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