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Question

(C) According to the de-Broglie equation,$\lambda = \frac{h}{mv}$.Rearranging for mass,we get $m = \frac{h}{\lambda v}$.Given: $h = 6.626 	imes 10^{-

Vedclass · Accepted Answer

$6.30 	imes 10^{-33} \ kg$

Vedclass · Answer

(C) According to the de-Broglie equation,$\lambda = \frac{h}{mv}$.Rearranging for mass,we get $m = \frac{h}{\lambda v}$.Given: $h = 6.626 	imes 10^{-34} \ kg \ m^2 \ s^{-1}$,$\lambda = 0.35 \ nm = 0.35 	imes 10^{-9} \ m$,and $v = c = 3 	imes 10^8 \ m \ s^{-1}$.Substituting the values: $m = \frac{6.626 	imes 10^{-34}}{0.35 	imes 10^{-9} 	imes 3 	imes 10^8} \ kg$.$m = \frac{6.626 	imes 10^{-34}}{1.05 	imes 10^{-1}} \ kg = 6.31 	imes 10^{-33} \ kg$.Therefore,the correct option is $C$.

Calculate the mass of a photon,if its wavelength is given as $0.35 \ nm$.

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