Calculate the molar mass of a nonvolatile sol | vedclass

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(B) The formula for boiling point elevation is $\Delta T_{b} = K_{b} \cdot m$,where $m$ is the molality of the solution.Molality $m = \frac{W_2 	imes

Vedclass · Accepted Answer

$175 \ g \ mol^{-1}$

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(B) The formula for boiling point elevation is $\Delta T_{b} = K_{b} \cdot m$,where $m$ is the molality of the solution.Molality $m = \frac{W_2 	imes 1000}{M_2 	imes W_1}$,where $W_2$ is the mass of solute,$M_2$ is the molar mass of solute,and $W_1$ is the mass of solvent.Substituting the values: $\Delta T_{b} = 0.01 \ K$,$K_{b} = 0.50 \ K \ kg \ mol^{-1}$,$W_2 = 0.35 \ g$,and $W_1 = 100 \ g$.$0.01 = 0.50 	imes \frac{0.35 	imes 1000}{M_2 	imes 100}$.$M_2 = \frac{0.50 	imes 0.35 	imes 1000}{0.01 	imes 100} = \frac{175}{1} = 175 \ g \ mol^{-1}$.

Calculate the molar mass of a nonvolatile solute if a solution containing $0.35 \ g$ of solute in $100 \ g$ of water has a boiling point elevation of $0.01 \ K$ $\left[K_{b}=0.50 \ K \ kg \ mol^{-1}\right]$.

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