Calculate the mole fraction of benzene in a s | vedclass

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Question

(A) Let the total mass of the solution be $100 \, g$ and the mass of benzene be $30 \, g$.$	herefore$ Mass of carbon tetrachloride $= (100 - 30) \, g

Vedclass · Accepted Answer

$0.458$

Vedclass · Answer

(A) Let the total mass of the solution be $100 \, g$ and the mass of benzene be $30 \, g$.$	herefore$ Mass of carbon tetrachloride $= (100 - 30) \, g = 70 \, g$.Molar mass of benzene $(C_6H_6) = (6 	imes 12 + 6 	imes 1) \, g \, mol^{-1} = 78 \, g \, mol^{-1}$.Number of moles of benzene $= \frac{30}{78} \, mol \approx 0.3846 \, mol$.Molar mass of $CCl_4 = (12 + 4 	imes 35.5) \, g \, mol^{-1} = 154 \, g \, mol^{-1}$.$	herefore$ Number of moles of $CCl_4 = \frac{70}{154} \, mol \approx 0.4545 \, mol$.Thus,the mole fraction of $C_6H_6$ is given as:$x_{C_6H_6} = \frac{n_{C_6H_6}}{n_{C_6H_6} + n_{CCl_4}} = \frac{0.3846}{0.3846 + 0.4545} = \frac{0.3846}{0.8391} \approx 0.458$.

Calculate the mole fraction of benzene in a solution containing $30\%$ by mass in carbon tetrachloride.

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