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(D) $1$. Calculate the molar mass of aluminium oxide $(Al_{2}O_{3})$:Molar mass = $(2 	imes 27) + (3 	imes 16) = 54 + 48 = 102 \, g/mol$.$2$. Determ

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$6.022 	imes 10^{20}$

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(D) $1$. Calculate the molar mass of aluminium oxide $(Al_{2}O_{3})$:Molar mass = $(2 	imes 27) + (3 	imes 16) = 54 + 48 = 102 \, g/mol$.$2$. Determine the number of moles in $0.051 \, g$ of $Al_{2}O_{3}$:Moles = $\frac{	ext{Given mass}}{	ext{Molar mass}} = \frac{0.051}{102} = 0.0005 \, mol = 5 	imes 10^{-4} \, mol$.$3$. Relate moles of $Al_{2}O_{3}$ to moles of $Al^{3+}$ ions:One mole of $Al_{2}O_{3}$ contains $2$ moles of $Al^{3+}$ ions.Therefore,$5 	imes 10^{-4} \, mol$ of $Al_{2}O_{3}$ contains $2 	imes 5 	imes 10^{-4} = 10^{-3} \, mol$ of $Al^{3+}$ ions.$4$. Calculate the number of ions:Number of ions = $	ext{Moles} 	imes 	ext{Avogadro's number} = 10^{-3} 	imes 6.022 	imes 10^{23} = 6.022 	imes 10^{20}$ ions.

Calculate the number of aluminium ions present in $0.051 \, g$ of aluminium oxide.
[Hint: The mass of an ion is the same as that of an atom of the same element. Atomic mass of $Al = 27 \, u$.]

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Calculate the number of aluminium ions present in $0.051 \, g$ of aluminium oxide.[Hint: The mass of an ion is the same as that of an atom of the same element. Atomic mass of $Al = 27 \, u$.]