Calculate the osmotic pressure of 0.5 M aque | vedclass

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Question

(B) The formula for osmotic pressure $(\pi)$ is given by $\pi = iCRT$. Since the solute is non-volatile and non-electrolyte,the van't Hoff factor $(i)

Vedclass · Accepted Answer

$12.32$

Vedclass · Answer

(B) The formula for osmotic pressure $(\pi)$ is given by $\pi = iCRT$. Since the solute is non-volatile and non-electrolyte,the van't Hoff factor $(i)$ is $1$. Given: Concentration $(C)$ = $0.5 \ M$ Temperature $(T)$ = $300 \ K$ Gas constant $(R)$ = $0.0821 \ atm \ dm^3 \ K^{-1} \ mol^{-1}$ Substituting the values: $\pi = 1 	imes 0.5 \ mol \ dm^{-3} 	imes 0.0821 \ atm \ dm^3 \ K^{-1} \ mol^{-1} 	imes 300 \ K$ $\pi = 0.5 	imes 0.0821 	imes 300 \ atm$ $\pi = 12.315 \ atm \approx 12.32 \ atm$. Therefore,the correct option is $B$.

Calculate the osmotic pressure of $0.5 \ M$ aqueous solution of a non-volatile solute at $300 \ K$ $\left[R = 0.0821 \ atm \ dm^3 \ K^{-1} \ mol^{-1}\right]$. (in $atm$)

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