Calculate the overall complex dissociation equilibrium constant for the $Cu(NH_3)_4^{2+}$ ion,given that $\beta_4$ for this complex is $2.1 \times 10^{13}$.

  • A
    $4.7 \times 10^{-14}$
  • B
    $2.1 \times 10^{-13}$
  • C
    $4.7 \times 10^{13}$
  • D
    $2.1 \times 10^{14}$

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