Calculate the solubility of a gas in a solvent at $25^{\circ} C$ and $0.8 \ atm$ if Henry's law constant for the solvent is $6.8 \times 10^{-4} \ mol \ dm^{-3} \ atm^{-1}$.
- A$5.88 \times 10^{-4} \ M$
- B$6.12 \times 10^{-4} \ M$
- C$5.44 \times 10^{-4} \ M$
- D$6.48 \times 10^{-4} \ M$
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