Calculate the total number of angular nodes and radial nodes present in $3p$ orbital.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(A) For $3p$ orbital,the principal quantum number $n = 3$ and the azimuthal quantum number $l = 1$.
The number of angular nodes is given by $l = 1$.
The number of radial nodes is given by $n - l - 1 = 3 - 1 - 1 = 1$.
Therefore,the $3p$ orbital has $1$ angular node and $1$ radial node.

Explore More

Similar Questions

Compare the energies of the following sets of quantum numbers for a multielectron system:
$A. n=4, \ell=1$
$B. n=4, \ell=2$
$C. n=3, \ell=1$
$D. n=3, \ell=2$
$E. n=4, \ell=0$
Choose the correct order of increasing energy from the options given below:

The electronic configuration of the ferric ion $(Fe^{3+})$ is:

In the ground state, an element has $13$ electrons in the $M$ shell. The element is

The electronic configuration of the valence shell of $Cu$ is $3d^{10}4s^{1}$ and not $3d^{9}4s^{2}$. How is this configuration explained?

If $n + l = 6$,then the total possible number of subshells would be

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo