Calculate the uncertainty in the position of an electron $(mass = 9.1 \times 10^{-28} \ g)$ moving with a velocity of $3 \times 10^4 \ cm \ sec^{-1}$,if the uncertainty in velocity is $0.011 \%$ (in $cm$)?

Uncertainty in the position of an electron (mass $= 9.1 \times 10^{-31} \, kg$) moving with a velocity $300 \, ms^{-1}$,with uncertainty $0.001\%$ will be :- $(h = 6.63 \times 10^{-34} \, Js)$

The moving bullet of a gun has $10 \ g$ mass and $10^{-5} \ m$ uncertainty in position. Find the uncertainty in velocity.

The uncertainty in the position of an electron $(\Delta x)$ is approximately $100 \ pm$. Calculate the uncertainty in momentum $(\Delta p)$ of the electron in $kg \ m \ s^{-1}$. $[h = 6.626 \times 10^{-34} \ J \ s]$

If the position of the electron is measured within an accuracy of $\pm 0.002 \,nm$,calculate the uncertainty in the momentum of the electron. Suppose the momentum of the electron is $\frac{h}{4 \pi \times 0.05 \,nm}$,is there any problem in defining this value?

Write down Heisenberg's uncertainty principle.