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(D) For a weak acid,the dissociation constant $K_a$ is given by the formula $K_a = C \alpha^2$,where $C$ is the concentration and $\alpha$ is the degr

Vedclass · Accepted Answer

$10^{-9}$

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(D) For a weak acid,the dissociation constant $K_a$ is given by the formula $K_a = C \alpha^2$,where $C$ is the concentration and $\alpha$ is the degree of dissociation.Given: Concentration $C = 0.1 \ M = 10^{-1} \ M$.Degree of dissociation $\alpha = 0.01 \% = \frac{0.01}{100} = 10^{-4}$.Substituting the values into the formula:$K_a = (10^{-1}) 	imes (10^{-4})^2$$K_a = 10^{-1} 	imes 10^{-8}$$K_a = 10^{-9}$.

Calculate the value of the dissociation constant $(K_a)$ of a weak acid,which dissociates to $0.01 \%$ in its $0.1 \ M$ solution.

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