Calculate the wave number and frequency of or | vedclass

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Question

(C) Given wavelength $\lambda = 6300 \ \mathring{A} = 6300 	imes 10^{-10} \ m = 6.3 	imes 10^{-7} \ m$. $(I)$ Wave number $(\bar{
u})$ is the recip

Vedclass · Accepted Answer

$1.587 	imes 10^6 \ m^{-1}, 4.761 	imes 10^{14} \ s^{-1}$

Vedclass · Answer

(C) Given wavelength $\lambda = 6300 \ \mathring{A} = 6300 	imes 10^{-10} \ m = 6.3 	imes 10^{-7} \ m$. $(I)$ Wave number $(\bar{
u})$ is the reciprocal of wavelength: $\bar{
u} = \frac{1}{\lambda} = \frac{1}{6.3 	imes 10^{-7} \ m} \approx 1.587 	imes 10^6 \ m^{-1}$. $(II)$ Frequency $(
u)$ is given by $
u = \frac{c}{\lambda}$,where $c = 3 	imes 10^8 \ m \ s^{-1}$: $
u = \frac{3 	imes 10^8 \ m \ s^{-1}}{6.3 	imes 10^{-7} \ m} \approx 4.761 	imes 10^{14} \ s^{-1}$. Thus,the correct option is $C$.

List-$I$	List-$II$
$(1)$ $X$-rays	$(A)$ $\nu = 10^0 - 10^4 \ Hz$
$(2)$ Ultraviolet $(UV)$ rays	$(B)$ $\nu = 10^{10} \ Hz$
$(3)$ Long radio waves	$(C)$ $\nu = 10^{16} \ Hz$
$(4)$ Microwave	$(D)$ $\nu = 10^{18} \ Hz$

Calculate the wave number and frequency of orange radiation having wavelength $6300 \ \mathring{A}$.

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$A$ photon of $300 \, nm$ is absorbed by a gas and then re-emits two photons. One re-emitted photon has a wavelength of $496 \, nm$. The wavelength of the second re-emitted photon is: (in $, nm$)

Match the following:

List-$I$ List-$II$

$(1)$ $X$-rays $(A)$ $\nu = 10^0 - 10^4 \ Hz$

$(2)$ Ultraviolet $(UV)$ rays $(B)$ $\nu = 10^{10} \ Hz$

$(3)$ Long radio waves $(C)$ $\nu = 10^{16} \ Hz$

$(4)$ Microwave $(D)$ $\nu = 10^{18} \ Hz$

The energy of electromagnetic radiation depends on:

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