Calculate the work done in joule if 1 mole o | vedclass

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(B) The work done in an irreversible process against constant external pressure is given by the formula: $W = -P_{ext} 	imes \Delta V$. Here,$P_{ext}

Vedclass · Accepted Answer

$4800$

Vedclass · Answer

(B) The work done in an irreversible process against constant external pressure is given by the formula: $W = -P_{ext} 	imes \Delta V$. Here,$P_{ext} = 4 \ bar = 4 	imes 10^5 \ Pa$. Initial volume $V_1 = 25 \ dm^3 = 25 	imes 10^{-3} \ m^3$. Final volume $V_2 = 13 \ dm^3 = 13 	imes 10^{-3} \ m^3$. Change in volume $\Delta V = V_2 - V_1 = (13 - 25) 	imes 10^{-3} \ m^3 = -12 	imes 10^{-3} \ m^3$. Substituting the values: $W = -(4 	imes 10^5 \ Pa) 	imes (-12 	imes 10^{-3} \ m^3) = 4800 \ J$. Since the gas is compressed,work is done on the system,so the value is positive.

Calculate the work done in joule if $1 \ mole$ of ideal gas is compressed from $25 \ dm^3$ to $13 \ dm^3$ at constant external pressure $4 \ bar$. (in $J$)

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