(B) In the reaction $Hexane \xrightarrow{\text{anhy. } AlCl_3 / HCl}$,the isomerization of $n$-hexane to branched alkanes occurs via a carbocation int

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

$Hexane \xrightarrow{\text{anhy. } AlCl_3 / HCl} \text{isomerization}$

(B) In the reaction $Hexane \xrightarrow{\text{anhy. } AlCl_3 / HCl}$,the isomerization of $n$-hexane to branched alkanes occurs via a carbocation intermediate.Option $A$ is a nucleophilic addition reaction.Option $C$ is a free radical substitution reaction.Option $D$ is a nucleophilic substitution reaction ($S_N2$ mechanism for primary halides).Therefore,the correct option is $B$.

Class 11 Chemistry 4 Organic Chemistry: Reaction Mechanism Reactive Intermediates

Medium

Carbocation as an intermediate is likely to be formed in the reaction:

KCET 2014 All KCET

A
$Acetone + HCN \xrightarrow{-OH} \text{acetone cyanohydrin}$
B
$Hexane \xrightarrow{\text{anhy. } AlCl_3 / HCl} \text{isomerization}$
C
$Propene + Cl_2 \xrightarrow{hv} 2-\text{chloropropane}$
D
$Ethyl bromide + \text{aq. } KOH \xrightarrow{\Delta} \text{ethyl alcohol}$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Chemistry Questions

Chapter

4 Organic Chemistry: Reaction Mechanism

Subtopic

Reactive Intermediates

Previous Year

KCET 2014 Paper All KCET years →

Rank the following radicals in order of increasing stability (least $ < < < $ most).

Medium

View Solution

The correct stability order for the following species is:
$(I)$ $o-CN-C_6H_4-CH_2^-$
$(II)$ $m-CN-C_6H_4-CH_2^-$
$(III)$ $p-CN-C_6H_4-CH_2^-$
$(IV)$ $C_6H_5-CH_2^-$
(Note: The image shows the structures of these carbanions.)

Medium

View Solution

Stability order of the following carbocations is:
$(i)$ $CH_3-C^{+}(CH_3)-CH_2-CH_3$
$(ii)$ $CH_3-CH^{+}-CH_3$
$(iii)$ $CH_3-C^{+}(CH_3)-CH_3$
$(iv)$ $Ph-CH^{+}-CH_3$

MediumAIIMS 2019

View Solution

Consider the following compounds:
$(I)$ $(CH_3)_3C-CH^{\bullet}-C_6H_5$
$(II)$ $(C_6H_5)_3C^{\bullet}$
$(III)$ $2$-methylbicyclo$[2.2.1]$hept$-2-$yl radical (as shown in the image)
Hyperconjugation occurs in:

MediumNEET 2015

View Solution

Identify the correct order of stability for carbocations.

Easy

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

Carbocation as an intermediate is likely to be formed in the reaction:

Similar Questions

Rank the following radicals in order of increasing stability (least $ < < < $ most).

The correct stability order for the following species is:$(I)$ $o-CN-C_6H_4-CH_2^-$$(II)$ $m-CN-C_6H_4-CH_2^-$$(III)$ $p-CN-C_6H_4-CH_2^-$$(IV)$ $C_6H_5-CH_2^-$(Note: The image shows the structures of these carbanions.)

Stability order of the following carbocations is:$(i)$ $CH_3-C^{+}(CH_3)-CH_2-CH_3$$(ii)$ $CH_3-CH^{+}-CH_3$$(iii)$ $CH_3-C^{+}(CH_3)-CH_3$$(iv)$ $Ph-CH^{+}-CH_3$

Consider the following compounds:$(I)$ $(CH_3)_3C-CH^{\bullet}-C_6H_5$$(II)$ $(C_6H_5)_3C^{\bullet}$$(III)$ $2$-methylbicyclo$[2.2.1]$hept$-2-$yl radical (as shown in the image)Hyperconjugation occurs in:

Identify the correct order of stability for carbocations.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The correct stability order for the following species is:
$(I)$ $o-CN-C_6H_4-CH_2^-$
$(II)$ $m-CN-C_6H_4-CH_2^-$
$(III)$ $p-CN-C_6H_4-CH_2^-$
$(IV)$ $C_6H_5-CH_2^-$
(Note: The image shows the structures of these carbanions.)

Stability order of the following carbocations is:
$(i)$ $CH_3-C^{+}(CH_3)-CH_2-CH_3$
$(ii)$ $CH_3-CH^{+}-CH_3$
$(iii)$ $CH_3-C^{+}(CH_3)-CH_3$
$(iv)$ $Ph-CH^{+}-CH_3$

Consider the following compounds:
$(I)$ $(CH_3)_3C-CH^{\bullet}-C_6H_5$
$(II)$ $(C_6H_5)_3C^{\bullet}$
$(III)$ $2$-methylbicyclo$[2.2.1]$hept$-2-$yl radical (as shown in the image)
Hyperconjugation occurs in: