A carbon resistor has a resistance specified | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The initial resistance $R_i$ is determined by the color code: Red $(2)$,Yellow $(4)$,Black $(10^0)$.$R_i = 24 	imes 10^0 \, \Omega = 24 \, \Omega

Vedclass · Accepted Answer

Brown,Red,Black

Vedclass · Answer

(A) The initial resistance $R_i$ is determined by the color code: Red $(2)$,Yellow $(4)$,Black $(10^0)$.$R_i = 24 	imes 10^0 \, \Omega = 24 \, \Omega$.When the resistor is cut into two pieces of equal length,the resistance of each piece becomes half of the original resistance because $R = ho \frac{L}{A}$.$R_f = \frac{R_i}{2} = \frac{24}{2} = 12 \, \Omega$.The new resistance $12 \, \Omega$ can be written as $12 	imes 10^0 \, \Omega$.According to the color code table: $1$ is Brown,$2$ is Red,and $10^0$ is Black.Therefore,the new color code is Brown,Red,Black.

$A$ carbon resistor has a resistance specified by three bands with colors red,yellow,and black. If this resistor is cut into two pieces of equal length,what will be the new color code of each piece? (Neglect the tolerance of the $4^{th}$ band)

Similar Questions

Explain the colour code used to determine the value of carbon film resistors.

$A$ carbon film resistor has colour code Green,Black,Violet,Gold. The value of the resistor is

The colour sequence in a carbon resistor is red,brown,orange and silver. The resistance of the resistor is

The colour code for a carbon resistor of resistance $0.2 \ k\Omega \pm 10 \%$ is

The resistance of a carbon resistor is $4.7 k \Omega \pm 5 \%$. The colour of the third band is

Vedclass Test Series

Exam Paper Generator

Online Exam Module