Cellulose upon acetylation with excess acetic | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Cellulose is a linear polymer of $\beta-D$-glucose units joined by $\beta-1,4$-glycosidic linkages. Each glucose unit in cellulose contains three

Vedclass · Accepted Answer

Vedclass · Answer

(A) Cellulose is a linear polymer of $\beta-D$-glucose units joined by $\beta-1,4$-glycosidic linkages. Each glucose unit in cellulose contains three hydroxyl $(-OH)$ groups (at $C_2, C_3,$ and $C_6$ positions). Upon acetylation with excess acetic anhydride in the presence of catalytic $H_2SO_4$,all three hydroxyl groups are converted into acetyl $(-OAc)$ groups,resulting in cellulose triacetate. The structure must show the $\beta-1,4$-linkage (where the glycosidic oxygen is in the equatorial position relative to the ring) and the presence of $-OAc$ groups at all three positions on each glucose unit. Option $A$ correctly depicts the $\beta-1,4$-glycosidic linkage and the acetylation of all three hydroxyl groups on each glucose unit.

Cellulose upon acetylation with excess acetic anhydride $/$ $H_2SO_4$ (catalytic) gives cellulose triacetate whose structure is

Similar Questions

What is invert sugar?

Which of the following phenomena is $NOT$ explained by the open chain structure of glucose?

Which carbohydrate is used in the silvering of mirrors?

Which carbon atom of glucose, numbered from $1$ to $6$, forms a hemiacetal structure by reacting with the $-CHO$ group to close the ring?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$I$. $CHO-CH(OH)-CH(OH)-CH(OH)-CH_2OH$	$II$. $CHO-CH(OH)-CH(OH)-CH(OH)-CH_2OH$
$III$. $CHO-CH(OH)-CH(OH)-CH(OH)-CH_2OH$