The centre of the circle $(x - 3)^2 + (y - 4)^2 = 5$ is

The equation of the circle in the first quadrant touching each coordinate axis at a distance of one unit from the origin is

$A$ circle touches the axes at the points $(3, 0)$ and $(0, -3)$. The centre of the circle is

Find the equation of the circle with centre $(-a, -b)$ and radius $\sqrt{a^{2}-b^{2}}$.

The parametric equations of the circle $x^2+y^2+2x-4y-4=0$ are

If the segments of the straight lines $x+y=6$ and $x+2y=4$ are two diameters of a circle passing through $(6,2)$,then the equation of that circle is