(D) The energy stored in a capacitor is given by the formula $U = \frac{1}{2}QV$.In the given graph,$Q$ is plotted on the $X$-axis and $V$ is plotted

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(D) The energy stored in a capacitor is given by the formula $U = \frac{1}{2}QV$.In the given graph,$Q$ is plotted on the $X$-axis and $V$ is plotted on the $Y$-axis.The area of the triangle $OAB$ is given by $\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$.Here,the base is $OB = Q$ and the height is $AB = V$.Therefore,$\text{Area} = \frac{1}{2} \times Q \times V = \frac{1}{2}QV$.This expression represents the energy stored in the capacitor.

Class 12 Physics Electrostatic Potential and Capacitance Energy Stored in a Capacitor

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The charge $Q$ on a capacitor varies with voltage $V$ as shown in the figure,where $Q$ is taken along the $X$-axis and $V$ along the $Y$-axis. The area of triangle $OAB$ represents

A
Capacitance
B
Capacitive reactance
C
Magnetic field between the plates
D
Energy stored in the capacitor

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Class 12 Questions

Class 12

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Electrostatic Potential and Capacitance

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Energy Stored in a Capacitor

$A$ charge of $40\,\mu C$ is given to a capacitor having capacitance $C = 10\,\mu F$. The stored energy in ergs is

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$A$ battery is used to charge a parallel plate capacitor until the potential difference between the plates becomes equal to the e.m.f. of the battery. The ratio of the energy stored in the capacitor to the work done by the battery will be

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Work done in placing a charge of $8 \times 10^{-18} \text{ C}$ on a capacitor of capacitance $800 \mu\text{F}$ is . . . . . . .

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$A$ parallel plate capacitor has a plate separation $d$ and plate area $A$. If it is charged to a potential $V$ and then disconnected from the battery,calculate the work done in increasing the separation between the plates to $2d$.

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Two capacitors,one of capacity $\frac{C}{2}$ and the other of capacity $C$,are connected to a battery of voltage $V$ as shown. The work done in charging both the capacitors fully is

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The charge $Q$ on a capacitor varies with voltage $V$ as shown in the figure,where $Q$ is taken along the $X$-axis and $V$ along the $Y$-axis. The area of triangle $OAB$ represents

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$A$ charge of $40\,\mu C$ is given to a capacitor having capacitance $C = 10\,\mu F$. The stored energy in ergs is

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