Check whether (0, 2) is a solution of the equ | vedclass

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(B) The given point is $(0, 2)$,which means $x = 0$ and $y = 2$.Substitute $x = 0$ and $y = 2$ into the equation $x - 2y = 4$:$L$.$H$.$S$. $= x - 2y =

Vedclass · Accepted Answer

No

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(B) The given point is $(0, 2)$,which means $x = 0$ and $y = 2$.Substitute $x = 0$ and $y = 2$ into the equation $x - 2y = 4$:$L$.$H$.$S$. $= x - 2y = 0 - 2(2) = 0 - 4 = -4$.The $R$.$H$.$S$. of the equation is $4$.Since $L$.$H$.$S$. $= -4$ and $R$.$H$.$S$. $= 4$,we have $L$.$H$.$S$. $
eq$ $R$.$H$.$S$.Therefore,$(0, 2)$ is not a solution of the equation $x - 2y = 4$.

Check whether $(0, 2)$ is a solution of the equation $x - 2y = 4$.

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