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(B) Given equation: $x(x+1)+8=(x+2)(x-2)$Expanding the left side: $x^2+x+8$Expanding the right side using the identity $(a+b)(a-b)=a^2-b^2$: $x^2-4$Eq

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(B) Given equation: $x(x+1)+8=(x+2)(x-2)$Expanding the left side: $x^2+x+8$Expanding the right side using the identity $(a+b)(a-b)=a^2-b^2$: $x^2-4$Equating both sides: $x^2+x+8=x^2-4$Subtracting $x^2$ from both sides: $x+8=-4$Rearranging the terms: $x+12=0$Since the highest power of the variable $x$ is $1$,it is a linear equation and not of the form $ax^2+bx+c=0$ (where $a 
eq 0$).Therefore,the given equation is not a quadratic equation.

Check whether the following is a quadratic equation:
$x(x+1)+8=(x+2)(x-2)$

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Check whether the following is a quadratic equation:$x(x+1)+8=(x+2)(x-2)$