Chlorine reacts with hot and concentrated NaO | vedclass

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Question

(A) The reaction of chlorine with hot and concentrated $NaOH$ is: $3 Cl_2 + 6 NaOH \rightarrow 5 NaCl + NaClO_3 + 3 H_2O$ Here,$(X)$ is $NaCl$ and $(Y

Vedclass · Accepted Answer

$1.67$

Vedclass · Answer

(A) The reaction of chlorine with hot and concentrated $NaOH$ is: $3 Cl_2 + 6 NaOH ightarrow 5 NaCl + NaClO_3 + 3 H_2O$ Here,$(X)$ is $NaCl$ and $(Y)$ is $NaClO_3$. $NaCl$ reacts with $AgNO_3$ to give a white precipitate of $AgCl$: $NaCl + AgNO_3 ightarrow AgCl \downarrow + NaNO_3$ In the chlorate ion $(ClO_3^-)$,the central $Cl$ atom is bonded to three oxygen atoms. There are $3$ resonance structures. The total number of bonds between $Cl$ and $O$ atoms across the resonance structures is $5$ (one double bond and two single bonds in each resonance contributor). Average bond order $= \frac{	ext{Total number of bonds}}{	ext{Number of resonating positions}} = \frac{5}{3} \approx 1.67$.

Chlorine reacts with hot and concentrated $NaOH$ and produces compounds $(X)$ and $(Y)$. Compound $(X)$ gives a white precipitate with silver nitrate solution. The average bond order between $Cl$ and $O$ atoms in $(Y)$ is

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