A chloro compound of vanadium has a spin-only | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The spin-only magnetic moment is given by the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.Given $\mu = 1.73 \

Vedclass · Accepted Answer

$VCl_4$

Vedclass · Answer

(B) The spin-only magnetic moment is given by the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.Given $\mu = 1.73 \ BM$,we have $1.73 = \sqrt{n(n+2)}$.Squaring both sides,$3 = n(n+2)$,which gives $n^2 + 2n - 3 = 0$.Solving for $n$,we get $(n+3)(n-1) = 0$,so $n = 1$ (since $n$ cannot be negative).Vanadium $(V)$ has the atomic number $23$ and electronic configuration $[Ar] 3d^3 4s^2$.For $n=1$,the vanadium ion must have one unpaired electron.In $VCl_4$,vanadium is in the $+4$ oxidation state $(V^{4+})$.The configuration of $V^{4+}$ is $[Ar] 3d^1$,which contains $1$ unpaired electron.Thus,the formula is $VCl_4$.

$A$ chloro compound of vanadium has a spin-only magnetic moment of $1.73 \ BM$. This vanadium chloride has the formula:

Similar Questions

German silver is an alloy of $Cu$ with

Which of the following compounds is colored?

The atomic radius of elements of which of the following series would be nearly the same?

If the $IUPAC$ name of an element is "unununium",then the correct statement regarding the element is:

The percentage $(\%)$ of iron in Mischmetal is ........ .

Vedclass Test Series

Exam Paper Generator

Online Exam Module