Choose the incorrect sentence.

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(D) The correct answer is $D$. $1$. The descending limb of the loop of Henle is permeable to water but nearly impermeable to electrolytes,which helps

Vedclass · Accepted Answer

Ascending limb of Henle's loop is impermeable to electrolytes.

Vedclass · Answer

(D) The correct answer is $D$. $1$. The descending limb of the loop of Henle is permeable to water but nearly impermeable to electrolytes,which helps in the concentration of filtrate. $2$. The distal convoluted tubule $(DCT)$ is capable of reabsorption of $HCO_3^-$ and selective secretion of hydrogen ions $(H^+)$,potassium ions $(K^+)$,and ammonia $(NH_3)$ to maintain the $pH$ and sodium-potassium balance in the blood. $3$. The collecting duct allows for the passage of small amounts of urea into the medullary interstitium to keep up the osmolarity and also secretes $H^+$ and $K^+$ ions. $4$. The ascending limb of the loop of Henle is impermeable to water but allows the transport of electrolytes (like $Na^+$,$Cl^-$,and $K^+$) actively or passively. Therefore,the statement that it is impermeable to electrolytes is incorrect.

Option	Ammonotelic	Ureotelic	Uricotelic
$a$	Pigeon,human	Aquatic amphibia,lizards	Cockroach,frog
$b$	Frog,lizards	Aquatic amphibia,humans	Cockroach,pigeon
$c$	Aquatic amphibia	Frog,human	Pigeon,lizards,cockroach
$d$	Aquatic amphibia	Cockroach,humans	Frog,pigeon,lizards

Similar Questions

Complete the following:
$(a)$ Urinary excretion = tubular reabsorption + tubular secretion -..........
$(b)$ Dialysis fluid = Plasma -..........

Assertion : Secreting hypotonic urine is effective in reducing urinary loss of water.
Reason : Hypotonic urine is more concentrated and higher in osmotic pressure than the blood.

$A$: Pregnant women may show some presence of glucose in their post-prandial urine although they have no diabetes.
$R$: In pregnant women,the glomerular filtration rate $(GFR)$ is slightly increased. As a result,the tubular load of glucose exceeds the tubular maximum for glucose reabsorption.

The volume of the filtrate per day is $X$ liters and the volume of urine released per day is $Y$ liters. It means about $Z$ $\%$ of the filtrate is reabsorbed by the process of reabsorption.

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