Choose the $CORRECT$ option for electric field components of unpolarized light passing through a polarizing sheet.
- AAn electric field component parallel to the polarizing direction is absorbed, and the component perpendicular to the polarizing direction is transmitted.
- BAn electric field component parallel to the polarizing direction is transmitted, and the component perpendicular to the polarizing direction is absorbed.
- CAn electric field component parallel to the polarizing direction is rotated through some angle, and the perpendicular component is transmitted.
- DAn electric field component parallel to the polarizing direction is transmitted, and the perpendicular component is rotated through some angle.
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Similar Questions
The figure shows four pairs of polarizing sheets,seen face-on. Each pair is mounted in the path of initially unpolarized light. The polarizing direction of each sheet (indicated by the dashed line) is referenced to either a horizontal $x$-axis or a vertical $y$-axis. Rank the pairs according to the fraction of the initial intensity that they pass,greatest first.
Easy
View SolutionUnpolarised light from air is incident on the surface of a transparent medium of refractive index $1.414$ such that the reflected light is completely polarised. Match the angles given in List-$I$ with the corresponding values given in List-$II$.
$A$. Angle of reflection $(i)$ $2 \sin^{-1} \left(\sqrt{\frac{2}{3}}\right)$ $B$. Angle of refraction $(ii)$ $\sin^{-1} \left(\sqrt{\frac{2}{3}}\right) - \sin^{-1} \left(\frac{1}{\sqrt{3}}\right)$ $C$. Angle between incident and completely polarised light $(iii)$ $\sin^{-1} \left(\frac{1}{\sqrt{3}}\right)$ $D$. Angle of deviation of the incident ray $(iv)$ $\cos^{-1} \left(\frac{1}{\sqrt{3}}\right)$
| $A$. Angle of reflection | $(i)$ $2 \sin^{-1} \left(\sqrt{\frac{2}{3}}\right)$ |
| $B$. Angle of refraction | $(ii)$ $\sin^{-1} \left(\sqrt{\frac{2}{3}}\right) - \sin^{-1} \left(\frac{1}{\sqrt{3}}\right)$ |
| $C$. Angle between incident and completely polarised light | $(iii)$ $\sin^{-1} \left(\frac{1}{\sqrt{3}}\right)$ |
| $D$. Angle of deviation of the incident ray | $(iv)$ $\cos^{-1} \left(\frac{1}{\sqrt{3}}\right)$ |
$A$ beam of unpolarised light of intensity $I_0$ is passed through a polaroid $A$ and then through another polaroid $B$ which is oriented so that its principal plane makes an angle of $45^{\circ}$ relative to that of $A$. The intensity of the emergent light is
The graph showing the dependence of intensity of transmitted light on the angle between polariser and analyser is ($I_0$ is intensity of plane polarised light)
Medium
View Solution$A$ beam of plane polarised light of large cross-sectional area and uniform intensity of $3.3 \, W m^{-2}$ falls normally on a polariser (cross-sectional area $3 \times 10^{-4} \, m^2$) which rotates about its axis with an angular speed of $31.4 \, rad/s$. The energy of light passing through the polariser per revolution is close to ........ $\times 10^{-4} \, J$.
DifficultJEE MAIN 2020
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