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(B) To solve this series,we look for a repeating pattern.Given series: $...baa...aab...a...a$Let's count the total number of blanks and letters. There

Vedclass · Accepted Answer

$aaba$

Vedclass · Answer

(B) To solve this series,we look for a repeating pattern.Given series: $...baa...aab...a...a$Let's count the total number of blanks and letters. There are $16$ positions in total.If we divide the series into groups of $4$,we get:$(baab) (baab) (baab) (baab)$By comparing the given series with this pattern:Original: $b a a b | b a a b | b a a b | b a a b$Missing letters: $b, a, a, b, a, b$Wait,let's re-examine the pattern based on the options.If we fill the blanks with $baab$:$b a a b | a a b a | a b a a | b a a b$Let's try the pattern $baab$:If we insert $baab$ into the blanks: $b a a b | a a b a | a b a a | b a a b$ does not fit.Let's test option $D$ $(baab)$:If we place $b, a, a, b$ in the blanks: $b b a a | b a a b | a b a a | b a a b$. This is not consistent.Let's test the pattern $aaba$:$a a b a | a a b a | a a b a | a a b a$Filling the blanks: $a a b a | a a b a | a a b a | a a b a$Original: $...baa...aab...a...a$Matches: $a a b a | a a b a | a a b a | a a b a$Thus,the missing letters are $a, a, b, a, a, b$. The correct option is $B$.

Choose the correct alternative to complete the series:
$...baa...aab...a...a$

Similar Questions

Study the following arrangement carefully and answer the question given below:
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Choose the correct alternative to complete the series:$...baa...aab...a...a$