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(A) To solve the series $....be...bb....aabc$,we look for a repeating pattern.Let the total number of characters be $16$. We can divide them into grou

Vedclass · Accepted Answer

$acac$

Vedclass · Answer

(A) To solve the series $....be...bb....aabc$,we look for a repeating pattern.Let the total number of characters be $16$. We can divide them into groups of $4$: $(....) (be..) (bb..) (aabc)$.By observing the pattern,we can test the sequence $aabc$ as the repeating unit.If we fill the blanks with $a, c, a, c$,the series becomes $aabc, aabc, aabc, aabc$.Thus,the missing letters are $a, c, a, c$.

Choose the correct alternative to complete the series: $....be...bb....aabc$

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