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(C) To solve this,we look for a repeating pattern in the series: $a . c . a b b . . a . b e . b e . . a b$.
By observing the sequence,we can divide i

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$b c c a a c$

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(C) To solve this,we look for a repeating pattern in the series: $a . c . a b b . . a . b e . b e . . a b$.
By observing the sequence,we can divide it into groups of $4$ or $5$ letters.
Let's test the pattern $a b c a / b b c a / b b e a / b b e a / b a b$.
Alternatively,looking at the structure $a b c a, b b c a, b b e a, b b e a, b a b$,it seems the pattern involves repeating segments.
By filling the blanks with $b, c, c, a, a, c$,the series becomes: $a b c a, b b c a, b b e a, b b e a, b a b$.
Thus,the correct sequence of letters to fill the blanks is $b, c, c, a, a, c$.

Choose the correct alternative to complete the series: $a . c . a b b . . a . b e . b e . . a b$

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Choose the correct alternative to complete the series: $a . c . a b b . . a . b e . b e . . a b$

Similar Questions

Find the missing letters for the given series from the given alternatives:$....aaba.....bba.....bba.....abaa....b$

Fill in the blank space for the given series with the correct alternative.$3, 7, 15, 31, 63, (\dots)$

Find out the wrong term from the given series.$1, 2, 6, 15, 31, 56, 91$

Fill in the blank space for the given series with the correct alternative.$2, 5, 11, 23, 47, (\ldots)$

Fill in the blank space for the given series with the correct alternative.$71, 76, 69, 74, 67, 72, (\ldots)$