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(C) To solve this,we divide the series into groups of $4$ letters each: $cccb | bbaa | ccbb | baaa | cc...$ Wait,let's re-examine the pattern. The ser

Vedclass · Accepted Answer

$baba$

Vedclass · Answer

(C) To solve this,we divide the series into groups of $4$ letters each: $cccb | bbaa | ccbb | baaa | cc...$ Wait,let's re-examine the pattern. The series is $cccb, bbaa, ccbb, baaa, cc...$ Let's try a different grouping: $cccb, bbaa, ccbb, aa...$ Actually,the pattern is $cccb, bbaa, ccbb, aa...$ Looking at the sequence: $c, c, c, b, b, b, a, a, a, c, c, c, b, b, b, a, a, a, c$. The missing letters are $b, a, b, a$. Thus,the sequence becomes $cccb, bbaa, ccbb, baaa, cc$. Therefore,the correct option is $baba$.

Choose the correct alternative to complete the series: $cccbb....aa....cc....bbbaa.....c$

Similar Questions

Choose the correct alternative to complete the series: $a . b e . . c . . a b b . . . b c a . . . .$

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How many such pairs of digits are there in the number $7326985$ each of which has as many digits between them in the given number as when the digits of the number are rearranged in ascending order within the number?

Find out the wrong term from the given series:
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