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Question

(B) To solve the series $aab....aa....bbb....aaa....bbba$,we look for a repeating pattern.By observing the sequence,we can group the letters as follow

Vedclass · Accepted Answer

$baab$

Vedclass · Answer

(B) To solve the series $aab....aa....bbb....aaa....bbba$,we look for a repeating pattern.By observing the sequence,we can group the letters as follows:$aa b / aa a bbb / aa a bbbb / a$.However,a more consistent pattern is $aa b / aa a bbb / aa a bbbb / a$ which is not standard.Let's re-examine the pattern: $aab / aabb / aaabb / aaabbb$.If we fill the blanks with $baab$,the series becomes $aab(b) / aa(a)bb(b) / aaabb(b) / aaabb(a)$.Actually,the most logical pattern is $aab / aabb / aaabb / aaabbb$.Filling the blanks with $baab$ results in $aab(b) / aa(a)bb(b) / aaabb(b) / aaabb(a)$,which completes the sequence $aab / aabb / aaabb / aaabbb$.

Choose the correct alternative to complete the series: $aab....aa....bbb....aaa....bbba$

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Choose the correct alternative to complete the series: $aab....aa....bbb....aaa....bbba$

Similar Questions

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