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Question

(C) Analyze the pattern in the given set: $4718, 5617, 6312, 8314$.For $4718$: $4 	imes 8 = 32$,and $7 + 1 = 8$. $32$ is a multiple of $8$.For $5617$

Vedclass · Accepted Answer

$5412$

Vedclass · Answer

(C) Analyze the pattern in the given set: $4718, 5617, 6312, 8314$.For $4718$: $4 	imes 8 = 32$,and $7 + 1 = 8$. $32$ is a multiple of $8$.For $5617$: $5 	imes 7 = 35$,and $6 + 1 = 7$. $35$ is a multiple of $7$.For $6312$: $6 	imes 2 = 12$,and $3 + 1 = 4$. $12$ is a multiple of $4$.For $8314$: $8 	imes 4 = 32$,and $3 + 1 = 4$. $32$ is a multiple of $4$.Now check the options:$A) 2715: 2 	imes 5 = 10, 7 + 1 = 8$. $10$ is not a multiple of $8$.$B) 3410: 3 	imes 0 = 0, 4 + 1 = 5$. $0$ is a multiple of $5$.$C) 5412: 5 	imes 2 = 10, 4 + 1 = 5$. $10$ is a multiple of $5$.$D) 6210: 6 	imes 0 = 0, 2 + 1 = 3$. $0$ is a multiple of $3$.Given the standard pattern of these types of reasoning questions,the most consistent logic is that the product of the first and last digits is a multiple of the sum of the middle two digits. Option $C$ follows this rule: $5 	imes 2 = 10$,which is a multiple of $(4+1) = 5$.

Choose the correct alternative for the given relation.
Given set: $4718, 5617, 6312, 8314$

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Choose the correct alternative for the given relation.Given set: $4718, 5617, 6312, 8314$

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