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(C) The $EAN$ (Effective Atomic Number) is calculated as $EAN = Z - X + Y$,where $Z$ is the atomic number of the metal,$X$ is the oxidation state,and

Vedclass · Accepted Answer

$NF - NF - F - F$

Vedclass · Answer

(C) The $EAN$ (Effective Atomic Number) is calculated as $EAN = Z - X + Y$,where $Z$ is the atomic number of the metal,$X$ is the oxidation state,and $Y$ is the number of electrons donated by ligands.$(I) \ [(Ph_3P)_2PdCl_2]$: $Pd$ is in $+2$ state. $EAN = 46 - 2 + (2 	imes 2) + (2 	imes 2) = 52$. Since $52 
eq 54$ $(Xe)$,it is $NF$.$(II) \ [NiBrCl(en)]$: $Ni$ is in $+2$ state. $EAN = 28 - 2 + (1 	imes 2) + (1 	imes 2) + (1 	imes 4) = 34$. Since $34 
eq 36$ $(Kr)$,it is $NF$.$(III) \ Na_4[Fe(CN)_5NOS]$: $Fe$ is in $+2$ state. $EAN = 26 - 2 + (5 	imes 2) + 2 = 36$. Since $36 = 36$ $(Kr)$,it is $F$.$(IV) \ Cr(CO)_3(NO)_2$: $Cr$ is in $0$ state. $EAN = 24 - 0 + (3 	imes 2) + (2 	imes 3) = 36$. Since $36 = 36$ $(Kr)$,it is $F$.

Choose the correct option regarding the following complex compounds which follows $(F)$ and does not follow $(NF)$ the Sidgwick $EAN$ rule:
$(I) \ [(Ph_3P)_2PdCl_2]$
$(II) \ [NiBrCl(en)]$
$(III) \ Na_4[Fe(CN)_5NOS]$
$(IV) \ Cr(CO)_3(NO)_2$
$(I) - (II) - (III) - (IV)$

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Choose the correct option regarding the following complex compounds which follows $(F)$ and does not follow $(NF)$ the Sidgwick $EAN$ rule:$(I) \ [(Ph_3P)_2PdCl_2]$$(II) \ [NiBrCl(en)]$$(III) \ Na_4[Fe(CN)_5NOS]$$(IV) \ Cr(CO)_3(NO)_2$$(I) - (II) - (III) - (IV)$