Choose the correct option regarding: Assertio | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The energy of an orbital in a hydrogen-like atom is given by $E_n = -13.6 	imes \frac{Z^2}{n^2} 	ext{ eV}$.As the principal quantum number $n$ i

Vedclass · Accepted Answer

Assertion is wrong,Reason is correct

Vedclass · Answer

(D) The energy of an orbital in a hydrogen-like atom is given by $E_n = -13.6 	imes \frac{Z^2}{n^2} 	ext{ eV}$.As the principal quantum number $n$ increases,the value of $E_n$ becomes less negative,meaning the total energy of the orbital increases.Therefore,the Assertion is incorrect.The Reason states that energy is required to move a negatively charged electron away from a positively charged nucleus,which is correct because work must be done against the electrostatic force of attraction.Thus,the Assertion is wrong,but the Reason is correct.The correct option is $(D)$.

Choose the correct option regarding: Assertion: Energy of the orbital decreases with increase of $n$.
Reason: Energy is required in shifting away the negatively charged electron from the positively charged nucleus.

Similar Questions

The electron in the $n^{th}$ orbit of $Li^{2+}$ is excited to $(n+1)$ orbit using the radiation of energy $1.47 \times 10^{-17} \ J$. The value of $n$ is $....$. Given $R_H = 2.18 \times 10^{-18} \ J$.

The energy of a photon is calculated by ......

The ratio of minimum wavelengths of Lyman and Balmer series will be $:-$

The series limit for the Balmer series of $H$ atom spectra is:

If the energy of the first orbit of $He^{+}$ is $-54.4 \, eV$,then the energy of the second orbit will be ............. $eV$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Choose the correct option regarding: Assertion: Energy of the orbital decreases with increase of $n$.Reason: Energy is required in shifting away the negatively charged electron from the positively charged nucleus.