Choose the correct order of C-C bond length i | vedclass

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(B) The $C-C$ bond length depends on the hybridization of the carbon atoms and the bond order.
$1$. $Acetylene$ $(HC \equiv CH)$: $sp$ hybridization,

Vedclass · Accepted Answer

$Acetylene < ethylene < benzene < graphite < ethane$

Vedclass · Answer

(B) The $C-C$ bond length depends on the hybridization of the carbon atoms and the bond order.
$1$. $Acetylene$ $(HC \equiv CH)$: $sp$ hybridization,triple bond,bond length $\approx 1.20 \ \mathring{A}$.
$2$. $Ethylene$ $(H_2C = CH_2)$: $sp^2$ hybridization,double bond,bond length $\approx 1.34 \ \mathring{A}$.
$3$. $Benzene$ $(C_6H_6)$: $sp^2$ hybridization,resonance hybrid,bond length $\approx 1.39 \ \mathring{A}$.
$4$. $Graphite$: $sp^2$ hybridization,delocalized $\pi$ electrons,bond length $\approx 1.42 \ \mathring{A}$.
$5$. $Ethane$ $(H_3C - CH_3)$: $sp^3$ hybridization,single bond,bond length $\approx 1.54 \ \mathring{A}$.
Thus,the correct order of bond length is $Acetylene < ethylene < benzene < graphite < ethane$.

Choose the correct order of $C-C$ bond length in the given compounds.

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