Choose the correct relationship between Poisson's ratio $(\sigma)$,bulk modulus $(K)$,and modulus of rigidity $(\eta)$ of a given solid object:
- A$\sigma=\frac{3 K -2 \eta}{6 K +2 \eta}$
- B$\sigma=\frac{6 K +2 \eta}{3 K -2 \eta}$
- C$\sigma=\frac{3 K+2 \eta}{6 K+2 \eta}$
- D$\sigma=\frac{6 K -2 \eta}{3 K -2 \eta}$
Explore More
Similar Questions
$A$ tension of $22 \,N$ is applied to a copper wire of cross-sectional area $0.02 \,cm^2$. Young's modulus of copper is $1.1 \times 10^{11} \,N/m^2$ and Poisson's ratio is $0.32$. The decrease in cross-sectional area will be:
$A$ material has a Poisson's ratio $0.5$. If a uniform rod of this material suffers a longitudinal strain of $2 \times 10^{-3}$,then the percentage change in its volume is
$A$ steel wire of length $2 \ m$ and Young's modulus $2.0 \times 10^{11} \ N/m^2$ is stretched by a force. If Poisson's ratio and transverse strain for the wire are $0.2$ and $10^{-3}$ respectively,then the elastic potential energy density of the wire is . . . . . . $\times 10^5 \ J/m^3$.
In materials like aluminium and copper, the correct order of magnitude of various elastic moduli is:
If there is no change in the volume of a wire upon stretching, then the Poisson's ratio for the material of the wire is:
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo