Choose the correct statement about two circle | vedclass

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(C) For the first circle $x^{2}+y^{2}-10x-10y+41=0$:Centre $A = (5, 5)$,Radius $R_{1} = \sqrt{5^{2}+5^{2}-41} = \sqrt{50-41} = \sqrt{9} = 3$.For the s

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Circles have only one meeting point

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(C) For the first circle $x^{2}+y^{2}-10x-10y+41=0$:Centre $A = (5, 5)$,Radius $R_{1} = \sqrt{5^{2}+5^{2}-41} = \sqrt{50-41} = \sqrt{9} = 3$.For the second circle $x^{2}+y^{2}-22x-10y+137=0$:Centre $B = (11, 5)$,Radius $R_{2} = \sqrt{11^{2}+5^{2}-137} = \sqrt{121+25-137} = \sqrt{146-137} = \sqrt{9} = 3$.The distance between the centres $AB = \sqrt{(11-5)^{2}+(5-5)^{2}} = \sqrt{6^{2}+0^{2}} = 6$.Since $AB = R_{1} + R_{2} = 3 + 3 = 6$,the circles touch each other externally.Therefore,the circles have only one meeting point.

Choose the correct statement about two circles whose equations are given below:
$x^{2}+y^{2}-10x-10y+41=0$
$x^{2}+y^{2}-22x-10y+137=0$

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Choose the correct statement about two circles whose equations are given below:$x^{2}+y^{2}-10x-10y+41=0$$x^{2}+y^{2}-22x-10y+137=0$