Choose the correct statement for the [Ni(CN)_ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. The atomic number of $Ni$ is $28$. Its electronic configuration is $[Ar] 3d^8 4s^2$.$2$. In $[Ni(CN)_4]^{2-}$, the oxidation state of $Ni$ is

Vedclass · Accepted Answer

The complex is square planar and diamagnetic

Vedclass · Answer

(C) $1$. The atomic number of $Ni$ is $28$. Its electronic configuration is $[Ar] 3d^8 4s^2$.$2$. In $[Ni(CN)_4]^{2-}$, the oxidation state of $Ni$ is $+2$, so the configuration of $Ni^{2+}$ is $[Ar] 3d^8$.$3$. $CN^-$ is a strong field ligand, which causes the pairing of electrons in the $3d$ orbitals.$4$. Due to this pairing, one $3d$ orbital becomes vacant, allowing $dsp^2$ hybridization.$5$. The $dsp^2$ hybridization results in a square planar geometry.$6$. Since all electrons are paired, the complex is diamagnetic.

Choose the correct statement for the $[Ni(CN)_4]^{2-}$ complex ion (Atomic number of $Ni=28$).

Similar Questions

Both $[Ni(CO)_4]$ and $[Ni(CN)_4]^{2-}$ are diamagnetic. The hybridization of nickel in these complexes,respectively,are

Which of the following complexes exhibits a square planar geometry?

$d^2sp^3$ hybridisation leads to

On the basis of valence bond theory,discuss the geometrical shapes and magnetic properties of the following $4$-coordinated complexes:
$(i)$ $[NiCl_{4}]^{2-}$
$(ii)$ $[Ni(CN)_{4}]^{2-}$
$(iii)$ $[Ni(CO)_{4}]$
$(iv)$ $MnO_{4}^{-}$

The spin-only magnetic moment of $[MnBr_4]^{x-}$ is $5.9 \ BM$. The geometry of the complex and $x$ respectively are

Vedclass Test Series

Exam Paper Generator

Online Exam Module