Choose the incorrect statement.

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(B) According to Gauss's law,the total electric flux through a closed surface is $\phi = \oint \vec{E} \cdot d\vec{A} = \frac{q_{	ext{net}}}{\varepsi

Vedclass · Accepted Answer

According to Gauss's law,if a closed surface encloses no charge,electric field must vanish everywhere on the surface.

Vedclass · Answer

(B) According to Gauss's law,the total electric flux through a closed surface is $\phi = \oint \vec{E} \cdot d\vec{A} = \frac{q_{	ext{net}}}{\varepsilon_0}$.If a closed surface encloses no charge $(q_{	ext{net}} = 0)$,the net flux through the surface must be zero.However,this does not imply that the electric field $\vec{E}$ must be zero everywhere on the surface.An external electric field can pass through the surface,entering at one point and exiting at another,resulting in a net flux of zero without the field vanishing everywhere.Therefore,statement $B$ is incorrect.

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