Choose the pair of species in which the oxida | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To find the oxidation number of nitrogen $(N)$ in each species:$1$. In $NO_2^-$: $x + 2(-2) = -1 \implies x - 4 = -1 \implies x = +3$.$2$. In $N_2

Vedclass · Accepted Answer

$NO_2^-, N_2O_3$

Vedclass · Answer

(A) To find the oxidation number of nitrogen $(N)$ in each species:$1$. In $NO_2^-$: $x + 2(-2) = -1 \implies x - 4 = -1 \implies x = +3$.$2$. In $N_2O_3$: $2x + 3(-2) = 0 \implies 2x - 6 = 0 \implies 2x = 6 \implies x = +3$.Since both $NO_2^-$ and $N_2O_3$ have nitrogen in the $+3$ oxidation state,the correct pair is $NO_2^-, N_2O_3$.

Choose the pair of species in which the oxidation number of nitrogen is the same.

Similar Questions

The oxidation number of $S$ in $S^{2-}$ is:

In which of the following compounds,does nitrogen exhibit the highest oxidation state?

Which of the following statements is correct regarding $H_2S_4O_6$?

In which of the following pairs is the difference in the oxidation number of the underlined elements the greatest?

The oxidation state of $Cr$ in $CrO_5$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module