Choose the reaction in which Delta H is not e | vedclass

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Question

(B) The relationship between enthalpy change $\Delta H$ and internal energy change $\Delta U$ is given by the equation: $\Delta H = \Delta U + \Delta

Vedclass · Accepted Answer

$C_2H_{4(g)} + H_{2(g)} 	o C_2H_{6(g)}$

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(B) The relationship between enthalpy change $\Delta H$ and internal energy change $\Delta U$ is given by the equation: $\Delta H = \Delta U + \Delta n_g RT$.If $\Delta n_g = 0$,then $\Delta H = \Delta U$.If $\Delta n_g 
eq 0$,then $\Delta H 
eq \Delta U$.Let us calculate $\Delta n_g$ (change in the number of moles of gaseous species) for each reaction:$A$: $\Delta n_g = 1 - 1 = 0$$B$: $\Delta n_g = 1 - (1 + 1) = -1$$C$: $\Delta n_g = 1 - 1 = 0$$D$: $\Delta n_g = 2 - (1 + 1) = 0$Since $\Delta n_g 
eq 0$ for option $B$,$\Delta H 
eq \Delta U$ in this reaction.

Choose the reaction in which $\Delta H$ is not equal to $\Delta U$.

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