Chromium hexacarbonyl,Cr(CO)_6,is an octahedr | vedclass

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(C) The central metal atom in $Cr(CO)_6$ is Chromium $(Cr)$.The atomic number of $Cr$ is $24$,and its electronic configuration is $[Ar] 3d^5 4s^1$.In

Vedclass · Accepted Answer

$d^2sp^3$

Vedclass · Answer

(C) The central metal atom in $Cr(CO)_6$ is Chromium $(Cr)$.The atomic number of $Cr$ is $24$,and its electronic configuration is $[Ar] 3d^5 4s^1$.In $Cr(CO)_6$,the oxidation state of $Cr$ is $0$ because $CO$ is a neutral ligand.$CO$ is a strong field ligand,which causes pairing of electrons in the $3d$ orbitals.The $3d$ orbitals become $t_{2g}^6 e_g^0$,leaving two $3d$ orbitals empty.These two $3d$ orbitals,one $4s$ orbital,and three $4p$ orbitals hybridize to form six $d^2sp^3$ hybrid orbitals.Thus,the hybridization is $d^2sp^3$ and the geometry is octahedral.

Chromium hexacarbonyl,$Cr(CO)_6$,is an octahedral compound involving which type of hybridization?

Similar Questions

$A$ complex with the composition $[MA_3B]^{n \pm}$ is found to have no geometrical isomers. The possible structure$(s)$ of the complex is/are (where $A$ and $B$ are monodentate ligands):

Identify the coordination complexes in which the central metal ion has $d^4$ configuration.
$(A)$ $[FeO_4]^{2-}$
$(B)$ $[Mn(CN)_6]^{3-}$
$(C)$ $[Fe(CN)_6]^{3-}$
$(D)$ $[Cr(H_2O)_6]^{2+}$
$(E)$ $[NiF_6]^{2-}$
Choose the correct answer from the options given below:

The hexachloridocobaltate $(III)$ ion is a high-spin complex. What is the possible hybridisation state of the cobalt ion in this complex?

Which of the following has a non-zero magnetic moment and $sp^3d^2$ hybridization?

Which of the following statements is not true?

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