Citrate,the first stable product of the Krebs | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In the Krebs cycle (Tricarboxylic Acid Cycle),$1$ molecule of citrate $(6C)$ is converted back to oxaloacetate $(4C)$.During this process,the foll

Vedclass · Accepted Answer

Four and two

Vedclass · Answer

(A) In the Krebs cycle (Tricarboxylic Acid Cycle),$1$ molecule of citrate $(6C)$ is converted back to oxaloacetate $(4C)$.During this process,the following steps occur:$1$. Decarboxylation: Two molecules of $CO_2$ are released. One during the conversion of isocitrate to $\alpha$-ketoglutarate,and another during the conversion of $\alpha$-ketoglutarate to succinyl-CoA.$2$. Oxidation: Four oxidation steps occur where $NAD^+$ or $FAD$ are reduced to $NADH$ or $FADH_2$. These are: $(i)$ Isocitrate to $\alpha$-ketoglutarate,(ii) $\alpha$-ketoglutarate to succinyl-CoA,(iii) Succinate to fumarate,and (iv) Malate to oxaloacetate.Therefore,there are $4$ oxidation steps and $2$ decarboxylation steps.

Citrate,the first stable product of the Krebs cycle,undergoes how many oxidation and decarboxylation steps respectively to regenerate oxaloacetate?

Similar Questions

Which enzyme is associated with the oxidative phosphorylation process in the $Kreb's$ cycle?

Pyruvate dehydrogenase activity during aerobic respiration requires

What is the connecting link between glycolysis and the Krebs cycle?

$(i)$ Label $A, B, C$ and $D$.
$(ii)$ How many $CO_2$ molecules are evolved between $A$ and Malic acid?
Choose the correct option from the following regarding the answers to the above questions $:-$

The product formed by the action of malate dehydrogenase is ....

Vedclass Test Series

Exam Paper Generator

Online Exam Module