Cold ferrous sulphate solution on absorption | vedclass

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Question

(A) The brown ring test involves the reaction of cold $FeSO_{4}$ solution with $NO$ gas to form the brown-colored complex $[Fe(H_{2}O)_{5}(NO)]SO_{4}$

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paramagnetic $[Fe(H_{2}O)_{5}(NO)]SO_{4}$

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(A) The brown ring test involves the reaction of cold $FeSO_{4}$ solution with $NO$ gas to form the brown-colored complex $[Fe(H_{2}O)_{5}(NO)]SO_{4}$.$FeSO_{4} + NO + 5H_{2}O \rightarrow [Fe(H_{2}O)_{5}(NO)]SO_{4}$In this complex, iron is in the $+1$ oxidation state ($d^7$ configuration). The $NO$ ligand acts as $NO^+$, making the iron center $Fe^+$. The complex exhibits a magnetic moment of $3.89 \ BM$, which corresponds to $3$ unpaired electrons, confirming it is paramagnetic.

Cold ferrous sulphate solution on absorption of $NO$ develops brown colour due to the formation of

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