The colour of a shining bright star is an indication of its

  • A
    Distance from the earth
  • B
    Size
  • C
    Temperature
  • D
    Mass

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The distribution of relative intensity $I(\lambda)$ of blackbody radiation from a solid object versus the wavelength $\lambda$ is shown in the figure. If the Wien displacement law constant is $2.9 \times 10^{-3} \ mK$,what is the approximate temperature of the object in $K$?

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The wavelength of maximum intensity of radiation emitted by a star is $289.8 \, nm$. The radiation intensity for the star is: (Stefan's constant $\sigma = 5.67 \times 10^{-8} \, W m^{-2} K^{-4}$,Wien's constant $b = 2898 \, \mu m \cdot K$)

$A$ black body has a maximum wavelength $\lambda_{m}$ at a temperature of $2200 \ K$. Its corresponding wavelength at a temperature of $3300 \ K$ will be:

Assume that for solar radiation,the surface temperature of the Sun is $6000 \,K$. If Wien's constant '$b$' is $2.897 \times 10^{-3} \,m-K$,the value of the maximum wavelength will be: (in $Å$)

$A$ black body at $1227\,^oC$ emits radiations with maximum intensity at a wavelength of $5000\,\mathring{A}$. If the temperature of the body is increased by $1000\,^oC$,the maximum intensity will be at ....... $\mathring{A}$.

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