Column II shows five systems in which two obj | vedclass

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(A) The force exerted by $X$ on $Y$ has a magnitude $Mg$:In $(p)$, block $Y$ moves with constant velocity, so net force is zero. The contact force exe

Vedclass · Accepted Answer

$(A) \rightarrow p, t; (B) \rightarrow q, s, t; (C) \rightarrow p, r, t; (D) \rightarrow q$

Vedclass · Answer

(A) The force exerted by $X$ on $Y$ has a magnitude $Mg$:In $(p)$, block $Y$ moves with constant velocity, so net force is zero. The contact force exerted by $X$ (normal + friction) balances its weight $Mg$.In $(t)$, sphere $Y$ falls with terminal (constant) velocity, so net force is zero. The force exerted by liquid $X$ (buoyant + viscous) balances its weight $Mg$.In $(q)$, $Z$ is in equilibrium, so it repels $Y$ downwards with force $Mg$. $Y$ is supported by $X$, so normal force from $X$ is $Mg + Mg = 2Mg$.In $(r)$, pulley $Y$ experiences tensions and its own weight, so force from $X$ is $\sqrt{(Mg)^2 + (Mg + m_0g)^2} 
eq Mg$.In $(s)$, $Y$ accelerates downwards, so buoyant force from $X$ is less than $Mg$.Thus, $(A)$ $ightarrow$ p, t.$(B)$ The gravitational potential energy of $X$ is continuously increasing:In $(q)$, the lift moves up, so the base $X$ moves up, increasing its $GPE$.In $(s)$ and $(t)$, as sphere $Y$ moves down, it displaces the liquid $X$ upwards. The center of mass of the liquid rises, so its $GPE$ increases.In $(p)$, $X$ is fixed. In $(r)$, $X$ moves down.Thus, $(B)$ $ightarrow$ q, s, t.$(C)$ Mechanical energy of the system $X+Y$ is continuously decreasing:In $(p)$, $Y$ moves down with constant $KE$, so its $GPE$ and mechanical energy decrease. $X$ is fixed.In $(r)$, both $X$ and $Y$ move down with constant velocity, so their $GPE$ and mechanical energy decrease

Column $I$	Column $II$
$(A)$ The force exerted by $X$ on $Y$ has a magnitude $Mg$.	$(p)$ Block $Y$ of mass $M$ on a fixed inclined plane $X$,slides on it with a constant velocity.
$(B)$ The gravitational potential energy of $X$ is continuously increasing.	$(q)$ Two ring magnets $Y$ and $Z$,each of mass $M$,are kept in a frictionless vertical plastic stand. $Y$ rests on base $X$ and $Z$ hangs in equilibrium. The system is in a lift moving up with constant velocity.
$(C)$ Mechanical energy of the system $X+Y$ is continuously decreasing.	$(r)$ $A$ pulley $Y$ of mass $m_0$ is fixed to a table $X$. $A$ block of mass $M$ hangs from a string over the pulley,fixed at $P$. The system is in a lift moving down with constant velocity.
$(D)$ The torque of the weight of $Y$ about point $P$ is zero.	$(s)$ $A$ sphere $Y$ of mass $M$ is released in a non-viscous liquid $X$ and moves down.
	$(t)$ $A$ sphere $Y$ of mass $M$ is falling with terminal velocity in a viscous liquid $X$.

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